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sebuah segitiga memiliki panjang alas 2x-5cm dan tinggi 3x+2cm. tentukan luas bangun segitiga tersebut!

Rani Maharani

Soal

Pembahasan

Luas segitiga = ½ x alas x tinggi

Diketahui:

alas = 2x-5 cm,

tinggi = 3x+2 cm

Luas segitiga

= ½ x (2x-5) x (3x+2)

= 3x² - 5x - 5 cm²

Jadi, luas segitiga adalah 3x² - 5x - 5 cm².

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