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Persamaan garis yang melalui (2, -3) dan bergradien 5?

Rani Maharani

Soal

Persamaan garis yang melalui (2, -3) dan bergradien 5?

Jawaban

Untuk menentukan persamaan garis yang melalui titik (2, -3) dan memiliki gradien 5, kita dapat menggunakan rumus:

$$y - y_1 = m(x - x_1)$$

dengan m adalah gradien garis dan (x₁, y₁) adalah koordinat titik yang dilalui garis.

Substitusi nilai yang diketahui:

$$\begin{aligned} y - (-3) &= 5(x - 2) \\ y + 3 &= 5x - 10 \\ y &= 5x - 13 \end{aligned}$$

Sehingga, persamaan garis yang melalui titik (2, -3) dan memiliki gradien 5 adalah y = 5x - 13.

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