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Suatu kumparan memiliki panjang kawat lilitan 1: meter dialiri kuat arus listrik 4 Amp. Jika kerapata medan magnet 8 Tesla, berapa besar gaya magnetnya

Rani Maharani

Soal

Jawaban

Diketahui:

Panjang kawat lilitan (l) = 1 meter

Kuat arus listrik yang mengalir (I) = 4 Ampere

Kerapatan medan magnet (B) = 8 Tesla

Untuk mencari besar gaya magnetnya, dapat menggunakan rumus:

F = BIL

dimana:

F = gaya magnet (dalam newton)

B = kerapatan medan magnet (dalam tesla)

I = kuat arus listrik yang mengalir (dalam ampere)

L = panjang kawat lilitan (dalam meter)

Substitusi nilai yang diketahui ke dalam rumus di atas:

F = 8 Tesla x 4 Ampere x 1 meter

F = 32 newton

Sehingga, besar gaya magnetnya adalah 32 newton.

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