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Tentukan nilai Stasioner dari f(x)=x^2-4x adalah…

Rani Maharani

Soal

Pembahasan

$f (x) = x^{2} - 4 x$ $�^{'} (�) = 2 � - 4$

Kemudian, kita mencari titik di mana f'(x) = 0: $2 � - 4 = 0$ $2 � = 4$ $� = 2$

Jadi, nilai stasioner dari fungsi f(x)=x^2-4x adalah x = 2

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