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Keliling alas sebuah tabung 88 cm sedangkan tinggi tabung 20 cm, hitunglah A. jari-jari alas tabung B. luas alas tabung

Rani Maharani

Soal

Keliling alas sebuah tabung 88 cm sedangkan tinggi tabung 20 cm, hitunglah

A. jari-jari alas tabung

B. luas alas tabung

C. luas tutup tabung

D. luas selimut tabung

F. luas permukaan/sisi tabung

jawaban

A. Jari-jari alas tabung:

Diketahui keliling alas tabung = 88 cm

Maka, 2 x π x r = 88

r = 88 / (2 x π)

r = 14 cm

B. Luas alas tabung:

Luas alas tabung = π x r^2

Luas alas tabung = π x (14)^2

Luas alas tabung = 616 cm^2

C. Luas tutup tabung:

Luas tutup tabung = π x r^2

Luas tutup tabung = π x (14)^2

Luas tutup tabung = 616 cm^2

D. Luas selimut tabung:

Luas selimut tabung = keliling alas x tinggi

Luas selimut tabung = 88 x 20

Luas selimut tabung = 1760 cm^2

E. Luas permukaan/sisi tabung:

Luas permukaan/sisi tabung = 2 x luas tutup + luas selimut

Luas permukaan/sisi tabung = 2 x 616 + 1760

Luas permukaan/sisi tabung = 2992 cm^2

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